S.G.L0AN
CR3DIT S0LUTI0NS
ZER0 DEP0SIT/UPFR0NT
10K x 58/M=190
20K x 58/M=380
50K x 58/M=930
100K x 58/M=1850
W/s:81697209(David Lee)
https://wa.me/+6581697209

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wa.me/6583481759

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If every male on earth got a boner at the same time, the earth's rotation would slow down. Assume there are about 3.8 billion males, with an average pen15 height of about 80 cm off the ground. The average pen15 weighs about 100 grams.

That's a combined mass of 380,000,000 kg of pen15s.

Now we must make an approximation. For simplicity's sake, let us assume the pen15 are all evenly lined up in a ring around the equator. The equation for moment of inertia of a ring is I = mass*radius^2. The radius of earth is about 6.371 million meters. Therefore the radius of the approximated pen15 ring is 6,371,000 + 0.80 = 6,371,000.8 meters.

I = 380,000,000*6,371,000.8^2 = 1.5424*10^22

The Earth has a moment of inertia, I = 8.04×10^37 kg*m^2. The Earth rotates at a moderate angular velocity of 7.2921159 ×10^−5 radians/second.